Question:
The major product of the following reaction is
The major product of the following reaction is
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Grignard reagents react with \(D_2O\) to replace the \(-MgX\) group by deuterium \((D)\).
Updated On: Jun 22, 2026
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The Correct Option is D
Solution and Explanation
Step 1: Formation of Grignard reagent.
The given compound is a vinylic bromide. In presence of magnesium and dry ether, it forms the corresponding Grignard reagent.
\[ \text{R--Br}+Mg \rightarrow \text{R--MgBr} \] Here, bromine is replaced by \[ MgBr \] at the same vinylic carbon.
Step 2: Reaction with \(D_2O\).
Grignard reagents react with heavy water \((D_2O)\) to give deuterated compounds.
\[ \text{R--MgBr}+D_2O \rightarrow \text{R--D}+MgBrOD \] Thus, the \(-MgBr\) group is replaced by deuterium \((D)\).
Step 3: Identify the product.
The double bond remains unchanged, and deuterium gets attached to the carbon where bromine was originally present.
Therefore, the product is deuterated cyclohexene, corresponding to option (4).
Step 4: Final conclusion.
Hence, the major product is \[ \boxed{\text{Option (4)}} \]
The given compound is a vinylic bromide. In presence of magnesium and dry ether, it forms the corresponding Grignard reagent.
\[ \text{R--Br}+Mg \rightarrow \text{R--MgBr} \] Here, bromine is replaced by \[ MgBr \] at the same vinylic carbon.
Step 2: Reaction with \(D_2O\).
Grignard reagents react with heavy water \((D_2O)\) to give deuterated compounds.
\[ \text{R--MgBr}+D_2O \rightarrow \text{R--D}+MgBrOD \] Thus, the \(-MgBr\) group is replaced by deuterium \((D)\).
Step 3: Identify the product.
The double bond remains unchanged, and deuterium gets attached to the carbon where bromine was originally present.
Therefore, the product is deuterated cyclohexene, corresponding to option (4).
Step 4: Final conclusion.
Hence, the major product is \[ \boxed{\text{Option (4)}} \]
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