Question:
Identify A, B, C, and D in the reactions (I), (II):
\[
\text{(I)}\quad xCl_2+yNaOH \rightarrow A+B+H_2O(l)
\]
(cold, dil)
\[
\text{(II)}\quad xCl_2+yNaOH \rightarrow C+D+H_2O(l)
\]
(hot, conc)
Identify A, B, C, and D in the reactions (I), (II):
\[
\text{(I)}\quad xCl_2+yNaOH \rightarrow A+B+H_2O(l)
\]
(cold, dil)
\[
\text{(II)}\quad xCl_2+yNaOH \rightarrow C+D+H_2O(l)
\]
(hot, conc)
Show Hint
Chlorine reacts with cold dilute NaOH to form \(NaCl\) and \(NaOCl\), while with hot concentrated NaOH it forms \(NaCl\) and \(NaClO_3\).
Updated On: Jun 26, 2026
- NaCl, HCl, NaOCl, NaClO\(_3\)
- NaCl, NaOCl, NaCl, NaClO\(_3\)
- NaCl, NaOCl\(_3\), NaCl, NaOCl
- NaOCl, Na\(_2\)O, NaOCl, NaO\(_2\)
Show Solution
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The Correct Option is B
Solution and Explanation
Step 1: Reaction of chlorine with cold and dilute NaOH.
When chlorine reacts with cold and dilute sodium hydroxide, it undergoes disproportionation reaction.
The balanced reaction is \[ Cl_2+2NaOH \rightarrow NaCl+NaOCl+H_2O \] Therefore, \[ A=NaCl \] and \[ B=NaOCl \]
Step 2: Reaction of chlorine with hot and concentrated NaOH.
When chlorine reacts with hot and concentrated sodium hydroxide, sodium chloride and sodium chlorate are formed.
The balanced reaction is \[ 3Cl_2+6NaOH \rightarrow 5NaCl+NaClO_3+3H_2O \] Therefore, \[ C=NaCl \] and \[ D=NaClO_3 \]
Step 3: Final conclusion.
Hence, \[ A=NaCl,\quad B=NaOCl,\quad C=NaCl,\quad D=NaClO_3 \] Therefore, the correct answer is \[ \boxed{\text{NaCl, NaOCl, NaCl, NaClO}_3} \] Hence, the correct option is \[ \boxed{(2)} \]
When chlorine reacts with cold and dilute sodium hydroxide, it undergoes disproportionation reaction.
The balanced reaction is \[ Cl_2+2NaOH \rightarrow NaCl+NaOCl+H_2O \] Therefore, \[ A=NaCl \] and \[ B=NaOCl \]
Step 2: Reaction of chlorine with hot and concentrated NaOH.
When chlorine reacts with hot and concentrated sodium hydroxide, sodium chloride and sodium chlorate are formed.
The balanced reaction is \[ 3Cl_2+6NaOH \rightarrow 5NaCl+NaClO_3+3H_2O \] Therefore, \[ C=NaCl \] and \[ D=NaClO_3 \]
Step 3: Final conclusion.
Hence, \[ A=NaCl,\quad B=NaOCl,\quad C=NaCl,\quad D=NaClO_3 \] Therefore, the correct answer is \[ \boxed{\text{NaCl, NaOCl, NaCl, NaClO}_3} \] Hence, the correct option is \[ \boxed{(2)} \]
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