Question:
Chlorine reacts separately with cold, dilute NaOH and hot, concentrated NaOH. Which of the following statements regarding these reactions is not correct?
Chlorine reacts separately with cold, dilute NaOH and hot, concentrated NaOH. Which of the following statements regarding these reactions is not correct?
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Cold = Hypochlorite; Hot = Chlorate. Both are disproportionation reactions.
Updated On: Jun 10, 2026
- Both are disproportionation reactions
- NaCl is a common product in both
- Hypochlorite ion is formed in cold, dilute conditions
- Perchlorate ion is formed in hot, concentrated conditions
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Disproportionation of Chlorine in basic media.
Step 2: Analysis
* Cold, dilute: $Cl_2 + 2NaOH \rightarrow NaCl + NaClO + H_2O$ (Hypochlorite). * Hot, concentrated: $3Cl_2 + 6NaOH \rightarrow 5NaCl + NaClO_3 + 3H_2O$ (Chlorate, not Perchlorate).
Step 3: Conclusion
Perchlorate ($ClO_4^-$) is not the product in hot concentrated NaOH; Chlorate ($ClO_3^-$) is. Statement (D) is incorrect.
Final Answer: (D)
Disproportionation of Chlorine in basic media.
Step 2: Analysis
* Cold, dilute: $Cl_2 + 2NaOH \rightarrow NaCl + NaClO + H_2O$ (Hypochlorite). * Hot, concentrated: $3Cl_2 + 6NaOH \rightarrow 5NaCl + NaClO_3 + 3H_2O$ (Chlorate, not Perchlorate).
Step 3: Conclusion
Perchlorate ($ClO_4^-$) is not the product in hot concentrated NaOH; Chlorate ($ClO_3^-$) is. Statement (D) is incorrect.
Final Answer: (D)
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