Total amount due on 1st April, 2022 = ₹4,00,000
To be paid in 2 equal annual instalments of ₹2,00,000 each
Interest @ 10% per annum to be paid on outstanding balance
31st March, 2023:
Interest = 10% of ₹4,00,000 = ₹40,000
Total due = ₹4,00,000 + ₹40,000 = ₹4,40,000
Payment made = ₹2,00,000 (1st instalment)
Balance carried forward = ₹2,40,000
31st March, 2024:
Interest = 10% of ₹2,40,000 = ₹24,000
Total due = ₹2,40,000 + ₹24,000 = ₹2,64,000
Payment made = ₹2,00,000 (2nd instalment)
Balance carried forward = ₹64,000
31st March, 2025:
Interest = 10% of ₹64,000 = ₹6,400
Final Payment = ₹64,000 + ₹6,400 = ₹70,400
| Date | Particulars | Amount (₹) | Date | Particulars | Amount (₹) |
|---|---|---|---|---|---|
| 2022 Apr 1 | To Balance b/d | 4,00,000 | 2023 Mar 31 | By Bank A/c (1st instalment) | 2,00,000 |
| 2023 Mar 31 | To Interest A/c | 40,000 | 2023 Mar 31 | By Balance c/d | 2,40,000 |
| 2023 Apr 1 | To Balance b/d | 2,40,000 | 2024 Mar 31 | By Bank A/c (2nd instalment) | 2,00,000 |
| 2024 Mar 31 | To Interest A/c | 24,000 | 2024 Mar 31 | By Balance c/d | 64,000 |
| 2024 Apr 1 | To Balance b/d | 64,000 | 2025 Mar 31 | By Bank A/c (final payment) | 70,400 |
| 2025 Mar 31 | To Interest A/c | 6,400 | |||
| Total | 7,74,400 | Total | 7,74,400 | ||
Final Answer: Iqbal's executor received a total of ₹7,74,400 including ₹74,400 as interest over 3 years.
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).