Question:
For a fixed amount of an ideal gas, its pressure is measured as a function of volume at three different temperatures ($T_1, T_2, T_3$). What is the correct order of temperatures?
figure [H]
For a fixed amount of an ideal gas, its pressure is measured as a function of volume at three different temperatures ($T_1, T_2, T_3$). What is the correct order of temperatures?
figure [H]
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Isotherms: The further away from the origin, the higher the temperature.
Updated On: Jun 6, 2026
- $T_3 < T_2 < T_1$
- $T_3 < T_1 < T_2$
- $T_2 < T_1 < T_3$
- $T_1 < T_2 < T_3$
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Ideal Gas Law $PV = nRT \rightarrow P = (nRT) \times (1/V)$.
Step 2: Meaning
For a constant volume, $P \propto T$. Higher curves in the $P-V$ graph correspond to higher temperatures.
Step 3: Analysis
Looking at the graph: the top curve is $T_2$, the middle is $T_1$, and the bottom is $T_3$. Thus, $T_3 < T_1 < T_2$.
Step 4: Conclusion
The order is $T_3 < T_1 < T_2$.
Final Answer: (B)
Ideal Gas Law $PV = nRT \rightarrow P = (nRT) \times (1/V)$.
Step 2: Meaning
For a constant volume, $P \propto T$. Higher curves in the $P-V$ graph correspond to higher temperatures.
Step 3: Analysis
Looking at the graph: the top curve is $T_2$, the middle is $T_1$, and the bottom is $T_3$. Thus, $T_3 < T_1 < T_2$.
Step 4: Conclusion
The order is $T_3 < T_1 < T_2$.
Final Answer: (B)
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