Find the inverse of each of the matrices(if it exists). \(\begin{bmatrix}1&-1&2\\0&2&-3\\3&-2&4\end{bmatrix}\)
Let A=\(\begin{bmatrix}1&-1&2\\0&2&-3\\3&-2&4\end{bmatrix}\)
By expanding along C1,we have :
IAI=1(8-6)-0+3(3-4)=2-3=-1
Now A11=8-6=2, A12=-(0+9)=-9, A13=0-6=-6
A21=-(-4+4)=0, A22=4-6=-2, A23=-(-2+3)=-1
A31=3-4=-1, A32=-(-3-0)=3, A33=2-0=2
so adj A=\(\begin{bmatrix}2&0&-1\\-9&-2&3\\-6&-1&2\end{bmatrix}\)
so A-1=\(\frac{1}{\mid A \mid}\)adj A=- \(\begin{bmatrix}2&0&-1\\-9&-2&3\\-6&-1&2\end{bmatrix}\)
=\(\begin{bmatrix}-2&0&1\\9&2&-3\\6&1&-2\end{bmatrix}\)
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Evaluate the determinants in Exercises 1 and 2.
\(\begin{vmatrix}2&4\\-5&-1\end{vmatrix}\)
Evaluate the determinants in Exercises 1 and 2.
(i) \(\begin{vmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{vmatrix}\)
(ii) \(\begin{vmatrix}x^2&-x+1&x-1\\& x+1&x+1\end{vmatrix}\)
Using properties of determinants,prove that:
\(\begin{vmatrix} x & x^2 & 1+px^3\\ y & y^2 & 1+py^3\\z&z^2&1+pz^3 \end{vmatrix}\)\(=(1+pxyz)(x-y)(y-z)(z-x)\)
Using properties of determinants,prove that:
\(\begin{vmatrix} 3a& -a+b & -a+c\\ -b+a & 3b & -b+c \\-c+a&-c+b&3c\end{vmatrix}\)\(=3(a+b+c)(ab+bc+ca)\)