Question:
During the standardisation of \(Na_2S_2O_3\) using \(K_2Cr_2O_7\) by the iodometric method, the equivalent weight of \(K_2Cr_2O_7\) is:
During the standardisation of \(Na_2S_2O_3\) using \(K_2Cr_2O_7\) by the iodometric method, the equivalent weight of \(K_2Cr_2O_7\) is:
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Each Cr atom changes oxidation state by 3, and there are 2 Cr atoms per formula unit.
Updated On: Jul 3, 2026
- Molecular weight/2
- Molecular weight/3
- Molecular weight/6
- Same as the molecular weight
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The Correct Option is C
Solution and Explanation
Step 1: Cr2O7(2-) + 14H+ + 6e- -> 2Cr3+ + 7H2O.
Step 2: Each Cr changes by 3, 2 Cr atoms = 6 electrons total.
Step 3: n-factor=6, equivalent weight=MW/6.
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