We are asked to differentiate \( x^2 \) with respect to \( x^3 \), so we need to use the chain rule. \[ \frac{d}{dx} \left( \frac{x^2}{x^3} \right) = \frac{d}{dx} \left( x^{2 - 3} \right) = \frac{d}{dx} \left( x^{-1} \right) \] \[ \frac{d}{dx} \left( x^{-1} \right) = -x^{-2} = \frac{2}{3x} \]
Step 2: Verify the options
The correct derivative is \( \frac{2}{3x} \), matching option (A).
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.