Step 1: {Analyze Assertion (A)}
For \( R \) to be reflexive, \( (x, x) \) must belong to \( R \) for all \( x \in \mathbb{N} \). This means \( x + x = 2x \) must be a prime number. However, for \( x>1 \), \( 2x \) is not a prime number as it is divisible by \( 2 \). Therefore, \( R \) is not reflexive, and Assertion (A) is true.
Step 2: {Analyze Reason (R)}
The Reason states that \( 2n \) is composite for all \( n \). This is false because when \( n = 1 \), \( 2n = 2 \), which is a prime number. Therefore, Reason (R) is false.
Step 3: {Conclusion}
Since Assertion (A) is true and Reason (R) is false, the correct answer is option (C).
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.