Step 1: Understanding the Concept:
The nucleophilic addition of \(HCN\) to carbonyl compounds depends on two factors:
1. Steric hindrance: Bulkier groups around the carbonyl carbon slow down the attack of the nucleophile.
2. Electronic factors: Electron-releasing alkyl groups reduce the electrophilicity (positive charge) of the carbonyl carbon.
Step 2: Detailed Explanation:
- Acetaldehyde (\(CH_3CHO\)): It is an aldehyde with only one methyl group and one hydrogen. It has the least steric hindrance and highest electrophilicity.
- Acetone (\(CH_3COCH_3\)): It is a ketone with two methyl groups. It has more steric hindrance and lower electrophilicity than acetaldehyde due to two \(+I\) groups.
- Di-tert. butyl ketone (\(((CH_3)_3C)_2CO\)): It has two extremely bulky tert-butyl groups. Steric hindrance is maximum here, making it the least reactive.
Step 3: Final Answer:
Order: Di-tert. butyl ketone \(<\) Acetone \(<\) Acetaldehyde.
(i) Explain Aldol condensation with example.
(ii) How are the following conversions achieved:
(a) Benzene Benzaldehyde, (b) Ethanoic acid ethanol.
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).