Arrange the following compounds as asked:
(a) In increasing order of pKb values: \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_6\text{H}_5\text{NHCH}_3 \), \( \text{C}_6\text{H}_5\text{NH}_2 \)
(b) In decreasing order of boiling point: \( \text{C}_2\text{H}_5\text{OH} \), \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{CH}_3)_2\text{NH} \)
(c) In decreasing order of solubility in water: \( \text{C}_6\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_2\text{H}_5\text{NH}_2 \)
(a) In increasing order of pKb values: \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_6\text{H}_5\text{NHCH}_3 \), \( \text{C}_6\text{H}_5\text{NH}_2 \)
Solution:
Lower pKb implies stronger base. Order of increasing pKb (i.e., decreasing basicity):
\( (\text{C}_2\text{H}_5)_2\text{NH} < \text{C}_2\text{H}_5\text{NH}_2 < \text{C}_6\text{H}_5\text{NHCH}_3 < \text{C}_6\text{H}_5\text{NH}_2 \)
Quick Tip:
Aromatic amines are weaker bases due to resonance; aliphatic amines are stronger.
(b) In decreasing order of boiling point: \( \text{C}_2\text{H}_5\text{OH} \), \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{CH}_3)_2\text{NH} \)
Solution:
Boiling point depends on hydrogen bonding and molecular weight. Order:
\( \text{C}_2\text{H}_5\text{OH} > \text{C}_2\text{H}_5\text{NH}_2 > (\text{CH}_3)_2\text{NH} \)
Quick Tip:
Alcohols have stronger H-bonding than amines, leading to higher boiling points.
(c) In decreasing order of solubility in water: \( \text{C}_6\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_2\text{H}_5\text{NH}_2 \)
Solution:
Solubility depends on ability to form H-bonds and size of hydrophobic group. Order:
\( \text{C}_2\text{H}_5\text{NH}_2 > (\text{C}_2\text{H}_5)_2\text{NH} > \text{C}_6\text{H}_5\text{NH}_2 \)
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.