An object A moving horizontally with kinetic energy of 800 J experiences a constant opposing force of 100 N, while moving from a place x to a place y, where xy is 2 m. What is the energy of A at y?
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Opposing forces reduce kinetic energy. Always use negative work for resistive forces.
Concept:
Work-energy theorem:
\[
W = \Delta K = K_f - K_i
\]
Work done by opposing force is negative:
\[
W = -F \cdot s
\]
Step 1: Work done by force.
\[
W = -100 \times 2 = -200 \, \text{J}
\]
Step 2: Final kinetic energy.
\[
K_f = K_i + W = 800 - 200 = 600 \, \text{J}
\]