The escape velocity from the surface of the earth is \( v_{e} \).
The escape velocity from the surface of a planet whose mass and radius are 3 times those of the earth will be:
Show Hint
- $v_{e}$
- $3v_{e}$
- $9v_{e}$
- $v_{e}/3$
The Correct Option is A
Solution and Explanation
Escape velocity $v_{e} = \sqrt{\frac{2GM}{R}}$.
Step 2: Analysis
$v_{p} = \sqrt{\frac{2G(3M)}{3R}} = \sqrt{\frac{2GM}{R}}$.
Step 3: Conclusion
The escape velocity remains the same as $v_{e}$.
Final Answer: (A)
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