Question

The potential energy of a simple harmonic oscillator at its mean position is:

• A. zero
• B. maximum
• C. half of maximum value
• D. none of these

Hint:

At mean position: $K.E.$ is max, $P.E.$ is min (zero). At extreme position: $P.E.$ is max, $K.E.$ is zero.

Answer 1

The Correct Option is A

Step 1: Concept
Potential energy $U = \frac{1}{2}kx^{2}$.
Step 2: Analysis
At the mean position, the displacement $x = 0$.
Step 3: Conclusion
Substituting $x = 0$ into the formula, $U = 0$.
Final Answer: (A)