Step 1: Understanding the Concept:
Acidity is determined by the stability of the conjugate base formed after the loss of a proton.
Step 2: Detailed Explanation:
When an \(\alpha\)-hydrogen is removed from an aldehyde or ketone, a carbanion (enolate ion) is formed.
This carbanion is stabilized by resonance with the adjacent electron-withdrawing carbonyl group (\( >C=O \)).
The negative charge is delocalized onto the more electronegative oxygen atom.
Additionally, the strong electron-withdrawing \( -I \) effect of the carbonyl group weakens the \( C_\alpha - H \) bond.
Step 3: Final Answer:
The acidity is due to the resonance stabilization of the resulting enolate ion.
(i) Explain Aldol condensation with example.
(ii) How are the following conversions achieved:
(a) Benzene Benzaldehyde, (b) Ethanoic acid ethanol.
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).