To solve the problem, we need to explain why chlorine gas (Cl₂) is liberated at the anode during the electrolysis of aqueous NaCl, even though oxygen gas (O₂) has a more positive standard electrode potential (\(E^\circ\)).
1. Electrolysis of Aqueous NaCl:
In the electrolysis of aqueous NaCl, two reactions take place at the electrodes: - At the anode (positive electrode), oxidation occurs (loss of electrons). - At the cathode (negative electrode), reduction occurs (gain of electrons). The ions present in aqueous NaCl are: - Na⁺ (sodium ions) - Cl⁻ (chloride ions) - H₂O (water molecules, which dissociate into H⁺ and OH⁻ ions)
2. Standard Electrode Potentials:
We are given that oxygen gas (O₂) has a more positive standard electrode potential compared to chlorine gas (Cl₂). The standard electrode potentials are as follows: - \( E^\circ_{\text{O}_2/\text{H}_2\text{O}} = +1.23 \, \text{V} \) (for the oxidation of water to oxygen) - \( E^\circ_{\text{Cl}_2/\text{Cl}^-} = +1.36 \, \text{V} \) (for the oxidation of chloride ions to chlorine gas) From these values, we see that chlorine gas (Cl₂) has a higher (more positive) electrode potential than oxygen gas (O₂), which suggests that Cl₂ should be favored at the anode.
3. Effect of Concentration and Overpotentials:
The reason chlorine gas (Cl₂) is actually liberated at the anode in the electrolysis of aqueous NaCl, rather than oxygen gas (O₂), can be explained by the following factors:
- Concentration Effect: In aqueous NaCl, the concentration of chloride ions (Cl⁻) is much higher than the concentration of water molecules (H₂O). This higher concentration of Cl⁻ ions means that the chloride ion oxidation reaction is more likely to occur at the anode, as there are more Cl⁻ ions available for oxidation.
- Overpotential: Overpotential refers to the extra voltage required to drive a particular oxidation or reduction reaction at an electrode, beyond the theoretical electrode potential. The overpotential for the evolution of oxygen gas (O₂) is relatively high, which makes the oxidation of chloride ions to chlorine gas (Cl₂) easier and more favorable under normal electrolysis conditions.
4. Final Answer:
Although oxygen gas (O₂) has a more positive standard electrode potential, chlorine gas (Cl₂) is liberated at the anode in the electrolysis of aqueous NaCl because: - Chloride ions (Cl⁻) are present in higher concentration in the solution. - The overpotential for oxygen gas (O₂) is high, making the oxidation of chloride ions to chlorine gas (Cl₂) more favorable. Thus, chlorine gas is preferentially produced at the anode.
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.