1. Calculation of Interest on Capital: Period = 6 months (from 1st Oct 2023 to 31st March 2024)
Interest for Aakash = ₹ 80,00,000 × 10% × (6/12) = ₹ 4,00,000
Interest for Baadal = ₹ 60,00,000 × 10% × (6/12) = ₹ 3,00,000
Total interest = ₹ 7,00,000
2. Remaining profit after interest: Net profit = ₹ 13,00,000 Less: Interest on capital = ₹ 7,00,000 Balance Profit = ₹ 6,00,000
3. Distribution of Balance Profit equally: Each partner’s share = ₹ 3,00,000 Total for Baadal = ₹ 3,00,000 (profit) + ₹ 3,00,000 (interest) = ₹ 6,00,000 Baadal’s guaranteed minimum = ₹ 7,00,000 Shortfall = ₹ 1,00,000 This shortfall shall be borne by Aakash.
Final Allocation: Aakash’s share = ₹ 3,00,000 – ₹ 1,00,000 = ₹ 2,00,000
Baadal’s share = ₹ 7,00,000
Profit and Loss Appropriation Account table { width: 80%; margin: 20px auto; border-collapse: collapse; font-family: Arial, sans-serif; } th, td { border: 1px solid black; padding: 10px; text-align: left; } th { background-color: #f2f2f2; } .total { font-weight: bold; } .note { width: 80%; margin: 10px auto; font-family: Arial, sans-serif; font-size: 14px; }
| Particulars | Amount (₹) | Particulars | Amount (₹) |
| To Interest on Capital – Aakash | 4,00,000 | By Net Profit b/d | 13,00,000 |
| To Interest on Capital – Baadal | 3,00,000 | ||
| To Aakash’s Capital A/c | 2,00,000 | ||
| To Baadal’s Capital A/c | 7,00,000 | ||
| Total | 16,00,000 | Total | 13,00,000 |
Note: There’s a deficiency of ₹ 3,00,000 in the P&L Appropriation A/c due to the guarantee adjustment. Here the deficiency of ₹ 1,00,000 is adjusted only between partners. The account technically shows the final appropriations.
Final Answer: Profit distribution completed as per guarantee.
Simar, Tanvi and Umara were partners in a firm sharing profits and losses in the ratio of 5:6:9. On 31st March, 2024 their Balance Sheet was as follows:

Umara died on 30th June, 2024. The partnership deed provided for the following on the death of a partner:
From the following information, prepare a Comparative Income Statement of Arun Ltd. for the year ended 31st March, 2024. 
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).