Step 1: Check reflexivity. For reflexivity, \( (x, x) \) must belong to \( R \), but \( x \) cannot be 5 cm shorter than itself. Thus, \( R \) is not reflexive.
Step 2: Check symmetry. For symmetry, if \( (x, y) \in R \), then \( (y, x) \in R \). Since \( x \) is 5 cm shorter than \( y \), the reverse is not true, so \( R \) is not symmetric.
Step 3: Check transitivity. For transitivity, if \( (x, y) \in R \) and \( (y, z) \in R \), then \( (x, z) \in R \). However, \( x \) is 5 cm shorter than \( y \) and \( y \) is 5 cm shorter than \( z \), making \( x \) 10 cm shorter than \( z \). Thus, \( R \) is not transitive.
Final Answer: \[ \boxed{\text{Neither transitive, nor symmetric, nor reflexive}} \]
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.