Question:

A particle moves along x-axis under force \(F(x) = -kx + ax^2\). Find nature of potential energy graph.

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Force is negative slope of potential → integrate carefully to get graph shape.
Updated On: Apr 23, 2026
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The Correct Option is D

Solution and Explanation

Concept: \[ F = -\frac{dU}{dx} \]

Step 1:
Find potential energy
\[ \frac{dU}{dx} = kx - ax^2 \] \[ U = \frac{kx^2}{2} - \frac{ax^3}{3} \]

Step 2:
Analyze shape

• Quadratic term $\Rightarrow$ upward curve initially
• Cubic term $\Rightarrow$ bends downward later So curve rises, then falls $\Rightarrow$ matches option (D) Conclusion: \[ {(D)} \]
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