Question:
A force of 10 N acts on a body of mass 20 kg for 10 s. Change in its momentum is:
A force of 10 N acts on a body of mass 20 kg for 10 s. Change in its momentum is:
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Impulse is the product of force and time. The change in momentum is equal to the impulse applied to the object.
Updated On: Apr 22, 2026
- 5 kg m/s
- 100 kg m/s
- 200 kg m/s
- 1000 kg m/s
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The Correct Option is B
Solution and Explanation
Step 1: Use the impulse-momentum theorem.
The change in momentum (\( \Delta p \)) is equal to the impulse applied to the object. Impulse is given by: \[ \Delta p = F \times \Delta t \] where: - \( F \) is the force applied, - \( \Delta t \) is the time for which the force acts.
Step 2: Substitute the given values.
Given that \( F = 10 \, \text{N} \) and \( \Delta t = 10 \, \text{s} \), we can substitute into the formula: \[ \Delta p = 10 \times 10 = 100 \, \text{kg m/s} \]
The change in momentum (\( \Delta p \)) is equal to the impulse applied to the object. Impulse is given by: \[ \Delta p = F \times \Delta t \] where: - \( F \) is the force applied, - \( \Delta t \) is the time for which the force acts.
Step 2: Substitute the given values.
Given that \( F = 10 \, \text{N} \) and \( \Delta t = 10 \, \text{s} \), we can substitute into the formula: \[ \Delta p = 10 \times 10 = 100 \, \text{kg m/s} \]
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