Question:

A diode and resistance are connected as shown in figures.

Out of the following statements, which one is true?
Diode in
A) fig (1) and fig (2) are both forward biased.
B) fig (1) and fig (2) are both reverse biased.
C) fig (1) is forward biased and in fig (2) is reverse biased.
D) fig (1) is reverse biased and in fig (2) is forward biased.

Show Hint

A diode conducts when its anode is at a higher potential than its cathode side.
Updated On: Oct 1, 2026
  • D
  • B
  • A
  • C
Show Solution
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
A p-n junction diode is forward biased when the p side (anode, the triangle base) is at a higher potential than the n side (cathode, the bar). Otherwise it is reverse biased.

Step 2: Key Formula or Approach:
In both figures the anode is on the left terminal and the cathode is joined to the resistor on the right.

Step 3: Detailed Explanation:
Fig. 1: the anode is at \(-5\) V and the other end is at \(-3\) V. The anode is at the lower potential (\(-5 < -3\)), so \(D_1\) is reverse biased.
Fig. 2: the anode is at \(0\) V and the other end is at \(-4\) V. The anode is at the higher potential (\(0 > -4\)), so \(D_2\) is forward biased.
So the true statement is: the diode in Fig. 1 is reverse biased and the diode in Fig. 2 is forward biased. This is statement D, which is listed as option A.

Final Answer:
Fig. 1 is reverse biased and Fig. 2 is forward biased, option (A). \[ \boxed{\text{Fig. 1 reverse, Fig. 2 forward}} \]
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