List of top Questions asked in JEE Main

In the above reaction ‘A’ is

Isobutyraldehyde on reaction with formaldehyde and K₂CO₃ gives compound ‘A’. Compound ‘A’ reacts with KCN and yields compound ‘B’, which on hydrolysis gives a stable compound ‘C’. The compound ‘C’ is

\(\begin{array}{l} I_n\left(x\right)=\int_0^x\frac{1}{\left(t^2+5\right)^n}dt, n=1, 2, 3,\cdots\end{array}\)

Then

Given below are two statements, one is Assertion (A) and other is Reason (R).

Assertion (A): Natural rubber is a linear polymer of isoprene called cis-polyisoprene with elastic properties.
Reason (R): The cis-polyisoprene molecules consist of various chains held together by strong polar interactions with coiled structure.

In the light of the above statements, choose the correct one from the options given below:

For the given reactions
Sn²⁺ + 2e^– → Sn
Sn⁴⁺ + 4e^– → Sn
the electrode potentials are;
\(E^{∘}_{Sn^{2+}/Sn}=−0.140V \) and \(E^{∘}_{Sn^{4+}Sn} =−0.010 V.\)
The magnitude of standard electrode potential for \(Sn^{4+}/Sn^{2+}\) i.e.
\(E^{∘}_{Sn^{4+}/Sn^{2+}}\)
is _________ × 10^–2 V. (Nearest integer)

The area of the bounded region enclosed by the curve 
\(y=3−|x−\frac{1}{2}|−|x+1| \)
and the x-axis is

Let x = x(y) be the solution of the differential equation 
\(2ye^{\frac{x}{y^2}}dx+(y^2−4xe^{\frac{x}{y^2}})dy=0 \)
such that x(1) = 0. Then, x(e) is equal to