Young's double slit experiment is performed with monochromatic light of wavelength \( 6000 \text{Ã…} \). If the intensity of light at a point on the screen where the path difference is \( 2000 \text{Ã…} \) is \( I_1 \) and the intensity of light at a point where path difference is \( 1000 \text{Ã…} \) is \( I_2 \), then the ratio \( I_1: I_2 \) is:
To determine the ratio \( I_1 : I_2 \) in Young's double slit experiment, we need to analyze the interference pattern and how the path difference affects the intensity of light at different points on the screen. 1. Given Data: - Wavelength of light, \( \lambda = 6000 \text{Ã…} \) - Path difference at point 1, \( \Delta_1 = 2000 \text{Ã…} \) - Path difference at point 2, \( \Delta_2 = 1000 \text{Ã…} \) - Intensity at point 1, \( I_1 \) - Intensity at point 2, \( I_2 \) 2. Calculate the Phase Difference: - The phase difference \( \phi \) is related to the path difference \( \Delta \) by: \[ \phi = \frac{2\pi \Delta}{\lambda} \] - For point 1: \[ \phi_1 = \frac{2\pi \times 2000 \text{Ã…}}{6000 \text{Ã…}} = \frac{2\pi}{3} \] - For point 2: \[ \phi_2 = \frac{2\pi \times 1000 \text{Ã…}}{6000 \text{Ã…}} = \frac{\pi}{3} \] 3. Calculate the Intensity: - The intensity \( I \) at a point on the screen is given by: \[ I = 4I_0 \cos^2\left(\frac{\phi}{2}\right) \] where \( I_0 \) is the intensity of light from a single slit. - For point 1: \[ I_1 = 4I_0 \cos^2\left(\frac{\phi_1}{2}\right) = 4I_0 \cos^2\left(\frac{\pi}{3}\right) = 4I_0 \left(\frac{1}{2}\right)^2 = I_0 \] - For point 2: \[ I_2 = 4I_0 \cos^2\left(\frac{\phi_2}{2}\right) = 4I_0 \cos^2\left(\frac{\pi}{6}\right) = 4I_0 \left(\frac{\sqrt{3}}{2}\right)^2 = 3I_0 \] 4. Determine the Ratio \( I_1 : I_2 \): - The ratio of the intensities is: \[ I_1 : I_2 = I_0 : 3I_0 = 1 : 3 \] 5. Final Answer: - The ratio \( I_1 : I_2 \) is: \[ \boxed{1:3} \] This corresponds to option (1).
N molecules each of mass m of gas A and 2N molecules each of mass 2m of gas B are contained in a vessel which is maintained at a temperature T. The mean square velocity of the molecules of gas B is denoted by V22 and the mean square of the x-component velocity of the molecules of gas B is denoted by V12, then V1\V2 is:
Among the following statements, the correct statement for a wave is:
Which of the following statements is true about LEDs