Let I = ∫x2ex dx
Taking \(x^2\) as first function and ex as second function and integrating by parts, we obtain
I= x2∫ex dx - ∫{\((\frac {d}{dx}x^2)\)∫exdx} dx
I = x2ex - ∫2x.exdx
I = x2ex-2∫x.ex dx
Again integrating by parts,we obtain
I =x2ex - 2[x.∫exdx - ∫{\((\frac {d}{dx}x)\).∫exdx} dx]
I = x2ex - 2[xex-∫exdx]
I = x2ex - 2[xex - ex]
I = x2ex - 2xex + 2ex + C
I = ex(x2 - 2x + 2) + C
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Find the area of the region bounded by the curve y2=x and the lines x=1,x=4 and the x-axis
Find the area of the region bounded by y2=9x, x=2, x=4 and the x-axis in the first quadrant.
Find the area of the region bounded by x2=4y,y=2,y=4 and the x-axis in the first quadrant.
Find the area of the region bounded by the ellipse \(\frac{x^2}{16}+\frac{y^2}{9}=1\)
The number of formulas used to decompose the given improper rational functions is given below. By using the given expressions, we can quickly write the integrand as a sum of proper rational functions.

For examples,
