Question:

With usual notations for a rigid body in rotational motion about a fixed axis, its

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\(L = I\omega\) is the rotational analogue of linear momentum \(p = mv\).
Updated On: Apr 24, 2026
  • kinetic energy is \(I\omega^{2}\)
  • angular momentum is \(I\omega\)
  • work done is \(\tau^{2}\omega^{2}\)
  • power is \(\tau \omega^{2}\)
  • angular velocity is \(\frac{d\omega}{dt}\)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
For rotational motion, angular momentum \(L = I\omega\).

Step 2:
Detailed Explanation:
1. Kinetic energy = \(\frac{1}{2}I\omega^2\), not \(I\omega^2\).
2. Angular momentum = \(I\omega\) — correct.
3. Work done = \(\tau \theta\), not \(\tau^2\omega^2\).
4. Power = \(\tau \omega\), not \(\tau \omega^2\).
5. Angular velocity = \(\omega\), \(\frac{d\omega}{dt}\) is angular acceleration.

Step 3:
Final Answer:
Angular momentum is \(I\omega\).
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