$\frac{R}{4}$
Step 1: The moment of inertia of a solid cylinder about its central axis is: \[ I = \frac{1}{2} M R^2 \] Step 2: The radius of gyration $K$ is related to the moment of inertia by: \[ I = M K^2 \] Step 3: Equating both expressions: \[ M K^2 = \frac{1}{2} M R^2 \] \[ K^2 = \frac{R^2}{2} \] \[ K = \frac{R}{\sqrt{2}} \] Step 4: Therefore, the correct answer is (C).
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
Kepler's second law (law of areas) of planetary motion leads to law of conservation of