Concept:
This question is based on basic properties of vectors, dot product, and cross product.
Step 1: Check statement A.
By triangle inequality:
\[
|\vec{a}+\vec{b}|\leq |\vec{a}|+|\vec{b}|
\]
So, A is true.
Step 2: Check statement B.
If two non-zero vectors are perpendicular, then:
\[
\vec{a}\cdot \vec{b}=|\vec{a}||\vec{b}|\cos 90^\circ
\]
\[
\vec{a}\cdot \vec{b}=0
\]
So, B is true.
Step 3: Check statement C.
By Cauchy-Schwarz inequality:
\[
|\vec{a}\cdot \vec{b}|\leq |\vec{a}||\vec{b}|
\]
So, C is true.
Step 4: Check statement D.
The cross product of two vectors is a vector, not a scalar.
So, D is false.
Step 5: Check statement E.
The dot product of two vectors is a scalar.
So, E is true.
Thus, correct statements are:
\[
A,\ B,\ C,\ E
\]
\[
\therefore \text{Correct Answer is (C)}
\]