Question:

Which of the following relation is correct? (\(v_{\mathrm{rms}}\): root mean square velocity, \(\bar{v}\): mean velocity and \(v_{\mathrm{mp}}\): most probable velocity)

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Remember the order: RMS \(>\) Average \(>\) Most probable.
Updated On: Apr 16, 2026
  • \( v_{\mathrm{rms}}>\bar{v}<v_{\mathrm{mp}} \)
  • \( v_{\mathrm{rms}} v_{\mathrm{mp}} \)
  • \( v_{\mathrm{rms}}>\bar{v}>v_{\mathrm{mp}} \)
  • None of these
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The Correct Option is C

Solution and Explanation

Concept:
For Maxwell–Boltzmann distribution: \[ v_{\mathrm{rms}} = \sqrt{\frac{3kT}{m}}, \quad \bar{v} = \sqrt{\frac{8kT}{\pi m}}, \quad v_{\mathrm{mp}} = \sqrt{\frac{2kT}{m}} \] Compare magnitudes \[ \sqrt{3}>\sqrt{\frac{8}{\pi}}>\sqrt{2} \] \[ \Rightarrow v_{\mathrm{rms}}>\bar{v}>v_{\mathrm{mp}} \]
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