Question:
Ideal gas insulated, heated by current through resistance \(100\Omega\), current \(1A\) for 5 min. Find change in internal energy.
Ideal gas insulated, heated by current through resistance \(100\Omega\), current \(1A\) for 5 min. Find change in internal energy.
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Insulated system $\Rightarrow$ all electrical energy goes into internal energy.
Updated On: Apr 23, 2026
- 0 kJ
- 30 kJ
- 10 kJ
- 20 kJ
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The Correct Option is B
Solution and Explanation
Concept:
\[
Q = I^2Rt
\]
Step 1: Calculate heat
\[ t = 5\times60 = 300s \] \[ Q = 1^2 \cdot 100 \cdot 300 = 30000J = 30kJ \]
Step 2: Insulated system
\[ \Delta U = Q = 30kJ \] Conclusion: \(30kJ\)
Step 1: Calculate heat
\[ t = 5\times60 = 300s \] \[ Q = 1^2 \cdot 100 \cdot 300 = 30000J = 30kJ \]
Step 2: Insulated system
\[ \Delta U = Q = 30kJ \] Conclusion: \(30kJ\)
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