Question:

Which of the following molecules shows \(\text{sp}^{3}\text{d}\) hybridisation?

Show Hint

sp3d hybridisation needs five electron domains on the central atom.
Updated On: Nov 12, 2026
  • \(\text{PCl}_{5}\)
  • \(\text{SO}_{2}\)
  • \(\text{BF}_{3}\)
  • \(\text{CO}_{2}\)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept
\(\text{sp}^{3}\text{d}\) hybridisation needs five electron domains around the central atom, giving a trigonal bipyramidal shape.

Step 2: Check the Options
In \(\text{PCl}_{5}\), P has five bond pairs and no lone pair, so it uses one 3s, three 3p and one 3d orbital.

Step 3: Why the other options fail
\(\text{SO}_{2}\) has three domains (\(\text{sp}^{2}\)). \(\text{BF}_{3}\) has three domains (\(\text{sp}^{2}\)). \(\text{CO}_{2}\) has two domains (sp).

Final Answer:
\(\text{PCl}_{5}\) shows \(\text{sp}^{3}\text{d}\) hybridisation. \[ \boxed{\text{(A) }\text{PCl}_{5}} \]
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