Question:
In the compound \(^1\text{CH}_2 = ^2\text{CH}-^3\text{CH}_2-^4\text{CH}_2-^5\text{C}\equiv ^6\text{CH}\), The \(C_2-C_3\) bond is of type
In the compound \(^1\text{CH}_2 = ^2\text{CH}-^3\text{CH}_2-^4\text{CH}_2-^5\text{C}\equiv ^6\text{CH}\), The \(C_2-C_3\) bond is of type
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Double bonded carbon is $sp^2$ and saturated carbon is $sp^3$.
Updated On: Oct 1, 2026
- \(sp-sp^2\)
- \(sp^3-sp^3\)
- \(sp-sp^3\)
- \(sp^2-sp^3\)
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The Correct Option is D
Solution and Explanation
Step 1: Hybridisation of each carbon
\(C_2\) is part of the \(C=C\) double bond, so it is \(sp^2\). \(C_3\) is a CH\(_2\) with only single bonds, so it is \(sp^3\).
Step 2: Bond
The \(C_2-C_3\) bond is formed by \(sp^2\) and \(sp^3\) overlap. Option (D).
Final Answer:
The bond is \(sp^2-sp^3\), option (D). \[ \boxed{\text{(D)}} \]
\(C_2\) is part of the \(C=C\) double bond, so it is \(sp^2\). \(C_3\) is a CH\(_2\) with only single bonds, so it is \(sp^3\).
Step 2: Bond
The \(C_2-C_3\) bond is formed by \(sp^2\) and \(sp^3\) overlap. Option (D).
Final Answer:
The bond is \(sp^2-sp^3\), option (D). \[ \boxed{\text{(D)}} \]
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