Question:
Identify the type of hybridization of carbon that is attached to the OH group, in benzylic alcohol?
Identify the type of hybridization of carbon that is attached to the OH group, in benzylic alcohol?
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The carbon bonded to OH in benzyl alcohol is a \(CH_2\) group with four single bonds.
Updated On: Oct 1, 2026
- \(sp\)
- \(sp^2\)
- \(sp^3\)
- \(dsp2\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Benzyl alcohol is \(\text{C}_6\text{H}_5\text{-CH}_2\text{-OH}\). The carbon carrying OH is the \(\text{CH}_2\) carbon, not a ring carbon.
Step 2: Count bonds:
This carbon forms four sigma bonds (with the ring carbon, two hydrogens and oxygen) and no pi bonds. Four sigma bonds mean \(sp^3\) hybridisation.
Step 3: Other options:
The ring carbons are \(sp^2\), which might tempt one to choose B, but the question asks about the carbon attached to OH. \(sp\) is for triple bonds, and \(dsp^2\) is for square planar metal complexes.
Final Answer:
The carbon is \(sp^3\) hybridised, option (C). \[ \boxed{sp^3} \]
Benzyl alcohol is \(\text{C}_6\text{H}_5\text{-CH}_2\text{-OH}\). The carbon carrying OH is the \(\text{CH}_2\) carbon, not a ring carbon.
Step 2: Count bonds:
This carbon forms four sigma bonds (with the ring carbon, two hydrogens and oxygen) and no pi bonds. Four sigma bonds mean \(sp^3\) hybridisation.
Step 3: Other options:
The ring carbons are \(sp^2\), which might tempt one to choose B, but the question asks about the carbon attached to OH. \(sp\) is for triple bonds, and \(dsp^2\) is for square planar metal complexes.
Final Answer:
The carbon is \(sp^3\) hybridised, option (C). \[ \boxed{sp^3} \]
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