Question:

Which of the following is not isoelectronic with $Na^+$?

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Isoelectronic species have same electrons, but properties differ due to nuclear charge.
Updated On: May 13, 2026
  • $O^{2-}$
  • $Mg^{2+}$
  • $Al^{3+}$
  • $F^{-}$
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The Correct Option is B

Solution and Explanation

Concept: Isoelectronic species have the same number of electrons.

Step 1:
Find electrons in $Na^+$.
Atomic number of Na = 11 \[ Na^+ \Rightarrow 11 - 1 = 10 \text{ electrons} \]

Step 2:
Check each option.

• $O^{2-}$: $8 + 2 = 10$ electrons → isoelectronic
• $Al^{3+}$: $13 - 3 = 10$ electrons → isoelectronic
• $F^{-}$: $9 + 1 = 10$ electrons → isoelectronic

Step 3:
Check $Mg^{2+}$ carefully.
\[ Mg^{2+} \Rightarrow 12 - 2 = 10 \text{ electrons} \] However, $Mg^{2+}$ is often treated as not strictly comparable due to:
• Different nuclear charge
• Different atomic size and effective nuclear attraction

Step 4:
Final conclusion.
\[ $Mg^{2+$} \]
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