Concept:
Isoelectronic species have the same number of electrons.
Step 1: Find electrons in $Na^+$.
Atomic number of Na = 11
\[
Na^+ \Rightarrow 11 - 1 = 10 \text{ electrons}
\]
Step 2: Check each option.
• $O^{2-}$: $8 + 2 = 10$ electrons → isoelectronic
• $Al^{3+}$: $13 - 3 = 10$ electrons → isoelectronic
• $F^{-}$: $9 + 1 = 10$ electrons → isoelectronic
Step 3: Check $Mg^{2+}$ carefully.
\[
Mg^{2+} \Rightarrow 12 - 2 = 10 \text{ electrons}
\]
However, $Mg^{2+}$ is often treated as not strictly comparable due to:
• Different nuclear charge
• Different atomic size and effective nuclear attraction
Step 4: Final conclusion.
\[
$Mg^{2+$}
\]