Question:
Which of the following is an aromatic alcohol?
Which of the following is an aromatic alcohol?
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An aromatic alcohol has OH on a side chain carbon, not directly on the ring.
Updated On: Oct 1, 2026
- I Only
- II and III Only
- I, II, III and IV
- I and IV Only
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
An aromatic alcohol (like benzyl alcohol) has the \(-\text{OH}\) group attached to an sp\(^3\) carbon of a side chain, and not directly to the benzene ring. If \(-\text{OH}\) sits on the ring, the compound is a phenol.
Step 2: Detailed Explanation:
The figure shows four structures.
(I) A benzene ring with \(-\text{OH}\) directly on the ring: phenol.
(II) A benzene ring with \(-\text{CH}_2\text{OH}\): benzyl alcohol, an aromatic alcohol.
(III) A ring with \(-\text{CH}_2\text{OH}\) and an ethyl group in the meta position: also an aromatic alcohol.
(IV) A ring with \(-\text{OH}\) directly on the ring and an ethyl group: a substituted phenol.
So only (II) and (III) are aromatic alcohols.
Step 3: Final Answer:
II and III only, option (B).
Final Answer:
Structures II and III have CH2OH on the ring. \[ \boxed{\text{(B) }\text{II and III only}} \]
An aromatic alcohol (like benzyl alcohol) has the \(-\text{OH}\) group attached to an sp\(^3\) carbon of a side chain, and not directly to the benzene ring. If \(-\text{OH}\) sits on the ring, the compound is a phenol.
Step 2: Detailed Explanation:
The figure shows four structures.
(I) A benzene ring with \(-\text{OH}\) directly on the ring: phenol.
(II) A benzene ring with \(-\text{CH}_2\text{OH}\): benzyl alcohol, an aromatic alcohol.
(III) A ring with \(-\text{CH}_2\text{OH}\) and an ethyl group in the meta position: also an aromatic alcohol.
(IV) A ring with \(-\text{OH}\) directly on the ring and an ethyl group: a substituted phenol.
So only (II) and (III) are aromatic alcohols.
Step 3: Final Answer:
II and III only, option (B).
Final Answer:
Structures II and III have CH2OH on the ring. \[ \boxed{\text{(B) }\text{II and III only}} \]
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