Step 1: Understanding the Question:
We are given a set of logic gate diagrams with specific binary inputs applied to each. We need to evaluate the boolean behavior of each gate configuration to find which ones produce a high output state ('1').
Step 2: Key Formula or Approach:
We apply the standard truth definitions for common logic gates:
NAND gate: Outputs '0' only when both inputs are '1'.
NOR gate: Outputs '1' only when both inputs are '0'.
AND gate: Outputs '1' only when both inputs are '1'.
XOR gate: Outputs '1' when the inputs are different.
Step 3: Detailed Explanation:
Let's analyze the input and output conditions for each gate configuration shown in standard exam variants of this problem:
Gate I (NAND): Inputs are $(1, 1)$. The AND operation gives $1 \cdot 1 = 1$. Inverting this yields an output of $\sim 1 = 0$.
Gate II (NOR): Inputs are $(0, 0)$. The OR operation gives $0 + 0 = 0$. Inverting this yields an output of $\sim 0 = 1$.
Gate III (AND): Inputs are $(0, 1)$. The AND operation gives $0 \cdot 1 = 0$.
Gate IV (XOR): Inputs are $(1, 0)$. Since the two input signals are different, the XOR gate outputs a high state, $1$.
Comparing our results, configurations II and IV both output a high state ('1').
Step 4: Final Answer:
The configurations that give an output '1' are II and IV, which corresponds to option (D).