Question

To get the truth table shown, from the following logic circuit, the Gate G should be }

• A. OR
• B. AND
• C. NOR
• D. NAND

Hint:

Logic Tip: The AND gate is the only common 2-input gate that produces the required low output for the second row of this specific circuit.

Answer 1

The Correct Option is B

Concept:
Analyzing the output $Y$ for different input combinations helps identify the logic of intermediate gates. 
Step 1: Analyze the truth table.
 

$A$	$B$	$Y$
0	0	0
0	1	0
1	0	1
1	1	1

Step 2: Evaluate the logic flow.
The final gate is an OR gate: \[ Y = A \text{ OR } C \]

• If $A = 0$ and $B = 1$, then $Y = 0$ (from table).
• For OR gate to give $0$, both inputs must be $0$.
• So, $C = 0$ when $(A, B) = (0,1)$.
• If Gate G were OR: $C = 0 \text{ OR } 1 = 1 \Rightarrow Y = 1$ (wrong).
• If Gate G is AND: $C = 0 \text{ AND } 1 = 0 \Rightarrow Y = 0$ (correct).

Final Conclusion:
\[ \boxed{\text{Gate G is an AND gate}} \]