Question:
An AND gate is followed by a NOT gate in series. With two inputs ' \(A\) ' and ' \(B\) ', the Boolean expression for the output ' \(Y\) ' will be
An AND gate is followed by a NOT gate in series. With two inputs ' \(A\) ' and ' \(B\) ', the Boolean expression for the output ' \(Y\) ' will be
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An AND gate followed by a NOT gate is equivalent to a single NAND gate.
Updated On: Apr 30, 2026
- \(\overline{A + B}\)
- \(\overline{A \cdot B}\)
- \(A \cdot B\)
- \(A + B\)
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The Correct Option is B
Solution and Explanation
Step 1: AND Gate Output
The output of an AND gate with inputs $A$ and $B$ is $(A \cdot B)$.
Step 2: NOT Gate Effect
The NOT gate inverts its input. So, if the input is $(A \cdot B)$, the final output $Y$ is the complement.
Step 3: Conclusion
The expression is $Y = \overline{A \cdot B}$, which represents a NAND gate.
Final Answer: (B)
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