Step 1: Hydrolysis
Ether \(R-O-R'\) with water gives \(ROH + R'OH\).
Step 2: Check options
Methoxymethane gives two molecules of methanol, the same compound. Methoxypropane gives methanol (1 C) and propanol (3 C), which differ by two carbons. Ethoxypropane gives ethanol (2 C) and propanol (3 C), which differ by one \(CH_2\) unit, so they are successive homologues. 1-Methoxypropane is the same as methoxypropane, so it gives methanol and propanol.
Step 3: Conclusion
The answer is ethoxypropane, option (C).
Final Answer:
Ethoxypropane gives ethanol and propan-1-ol.
\[ \boxed{\text{(C)}\ \text{Ethoxypropane}} \]