Step 1: Understanding the Concept
Coloured compounds arise from d-d electron transitions. These need at least one d electron and at least one empty d orbital.
Step 2: Detailed Explanation
\(\text{Sc}^{3+}\): \([\text{Ar}]\) \(3d^0\), no d electrons, so it is colourless.
\(\text{Ni}^{3+}\): \(3d^7\), \(\text{Cr}^{3+}\): \(3d^3\), \(\text{V}^{3+}\): \(3d^2\). All have partly filled d orbitals, so they are coloured.
Final Answer:
Sc in +3 state gives colourless compounds, option (A).
\[ \boxed{\text{Sc}} \]