Question:

Which of the aromatic compounds react fastest with methoxide ion?

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SNAr speed: ortho/para –NO$_2$ >> meta –NO$_2$.
Updated On: Apr 23, 2026
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The Correct Option is B

Solution and Explanation

Concept: Nucleophilic Aromatic Substitution (SNAr).

Step 1:
Reaction requires electron-withdrawing group (–NO$_2$) to stabilize intermediate.

Step 2:
Activation is strongest at ortho/para positions relative to leaving group.

Step 3:
Para –NO$_2$ in option (b) stabilizes Meisenheimer complex effectively.

Step 4:
Meta substitution (d) gives less stabilization.

Step 5:
No/poor EWG cases react slowly or not at all.
Conclusion:
Option (b) reacts fastest.
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