Question:
For the constructive interference the path difference between the two interfering waves must be equal to
For the constructive interference the path difference between the two interfering waves must be equal to
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Constructive = $n\lambda$ (Path) or $2n\pi$ (Phase). Destructive = $(2n+1)\lambda/2$ (Path).
Updated On: Apr 10, 2026
- $(2n+1)\lambda$
- $2n\pi$
- $n\lambda$
- $(2n+1)\frac{\lambda}{2}$
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The Correct Option is C
Solution and Explanation
Step 1: Formula
Phase difference is related to path difference by the formula: $\Delta\phi = \frac{2\pi}{\lambda}\Delta x$.
Step 2: Condition
For constructive interference, the phase difference must be an even multiple of $\pi$, i.e., $\Delta\phi = 2n\pi$ (where $n = 0, 1, 2, ...$).
Step 3: Calculation
Substituting this into the formula: $2n\pi = \frac{2\pi}{\lambda}\Delta x \Rightarrow \Delta x = n\lambda$.
Final Answer: (c)
Phase difference is related to path difference by the formula: $\Delta\phi = \frac{2\pi}{\lambda}\Delta x$.
Step 2: Condition
For constructive interference, the phase difference must be an even multiple of $\pi$, i.e., $\Delta\phi = 2n\pi$ (where $n = 0, 1, 2, ...$).
Step 3: Calculation
Substituting this into the formula: $2n\pi = \frac{2\pi}{\lambda}\Delta x \Rightarrow \Delta x = n\lambda$.
Final Answer: (c)
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