Question:

Which of the following reagents are used to convert propene to propyne?

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Alkene → Alkyne = halogen addition + double elimination.
Updated On: Apr 14, 2026
  • SOCl$_2$/Py, alc. KOH, H$^+$/H$_2$O
  • Br$_2$/CCl$_4$, alc. KOH/$\Delta$
  • alc. KCN, SOCl$_2$
  • alc. KOH, B$_2$H$_6$/H$_2$O$_2$
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The Correct Option is B

Solution and Explanation

Concept: To convert alkene → alkyne:
•First add halogen → vicinal dihalide
•Then eliminate HX twice using strong base

Step 1:
\[ \text{Propene} \xrightarrow{\mathrm{Br_2/CCl_4}} \text{vicinal dibromide} \]

Step 2:
\[ \xrightarrow{\text{alc. KOH / } \Delta} \text{Propyne} \] \[ \therefore \text{correct answer = (B) Br$_2$/CCl$_4$, alc. KOH/$\Delta$} \]
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