Question:

Which compound is formed on catalytic hydrogenation of carbon monoxide at high pressure and high temperature in presence of \(ZnO-Cr_2O_3\) catalyst? 
 

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Methanol is industrially prepared by catalytic hydrogenation of carbon monoxide: \[ CO+2H_2\rightarrow CH_3OH \] using \(ZnO-Cr_2O_3\) catalyst under high temperature and pressure.
Updated On: Jun 22, 2026
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The Correct Option is A

Solution and Explanation

Step 1: Recall the catalytic hydrogenation of carbon monoxide.
Carbon monoxide reacts with hydrogen gas under high pressure and high temperature in the presence of \[ ZnO-Cr_2O_3 \] catalyst to form methanol.
The reaction is: \[ CO+2H_2 \overset{ZnO-Cr_2O_3}{\longrightarrow} CH_3OH \]

Step 2: Identify the product formed.
From the reaction, \[ CH_3OH \] is produced.
This compound is methanol (methyl alcohol).

Step 3: Eliminate the incorrect options.
\[ CH_3COOH \] is acetic acid and is not formed in this reaction.
\[ CH_3CH_2OH \] is ethanol, which is also not obtained by this catalytic hydrogenation.
Phenol is an aromatic alcohol and is unrelated to this process.

Step 4: Final conclusion.
Therefore, the compound formed is \[ \boxed{CH_3OH} \]
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