Question:

When vapours of alcohol X are passed over heated copper at \(573\ K\), it gives an alkene. What is X?

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At 573 K with Cu: Primary → Aldehyde, Secondary → Ketone, Tertiary → Alkene.
Updated On: Jul 29, 2026
  • \(CH_3CH_2CH_2CH_2OH\)
  • \((CH_3)_2CH-CH_2OH\)
  • \((CH_3)_3C-OH\)
  • \(CH_3CH(OH)CH_2CH_3\)
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The Correct Option is C

Solution and Explanation

Concept: When alcohol vapours are passed over heated copper at: \[ 573K \] the reaction depends on the type of alcohol: Primary alcohol: \[ \text{Dehydrogenation} \rightarrow \text{Aldehyde} \] Secondary alcohol: \[ \text{Dehydrogenation} \rightarrow \text{Ketone} \] Tertiary alcohol: \[ \text{Dehydration} \rightarrow \text{Alkene} \]

Step 1: Check Option (A) \[ CH_3CH_2CH_2CH_2OH \] This is a primary alcohol. It gives aldehyde. Not alkene.

Step 2: Check Option (B) \[ (CH_3)_2CHCH_2OH \] This is also a primary alcohol. It gives aldehyde. Not alkene.

Step 3: Check Option (C) \[ (CH_3)_3COH \] This is tert-butyl alcohol (tertiary alcohol). Tertiary alcohol undergoes dehydration to form: \[ (CH_3)_2C=CH_2 \] (an alkene) So correct.

Step 4: Check Option (D) \[ CH_3CH(OH)CH_2CH_3 \] This is a secondary alcohol. It gives ketone. Not alkene. Thus, \[ \boxed{(CH_3)_3COH} \] Therefore, the correct answer is: \[ \boxed{(C)} \]
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