When a parallel beam of light enters a water surface obliquely, the beam undergoes refraction due to the change in the speed of light when passing from one medium (air) to another (water). Let's break down the effect of this refraction on the width of the beam:
When light passes from air (where the refractive index is approximately 1) into water (with a refractive index of about 1.33), the change in speed causes the light to bend according to Snell's law. The refractive index (\( n \)) is related to the angle of incidence (\( \theta_1 \)) and the angle of refraction (\( \theta_2 \)) as:
\[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \]
where:When the light enters the water obliquely, the beam bends, causing the light rays to spread out more (or less) depending on the direction of the incident light. Since the speed of light in water is slower, the light rays are refracted towards the normal, causing the beam to become narrower in the direction of propagation.
When a parallel beam of light enters the water surface obliquely, the width of the beam decreases due to the refraction of light as it slows down and bends towards the normal. The greater the angle of incidence, the more pronounced the narrowing of the beam.
\(XPQY\) is a vertical smooth long loop having a total resistance \(R\), where \(PX\) is parallel to \(QY\) and the separation between them is \(l\). A constant magnetic field \(B\) perpendicular to the plane of the loop exists in the entire space. A rod \(CD\) of length \(L\,(L>l)\) and mass \(m\) is made to slide down from rest under gravity as shown. The terminal speed acquired by the rod is _______ m/s. 
A biconvex lens is formed by using two plano-convex lenses as shown in the figure. The refractive index and radius of curvature of surfaces are also mentioned. When an object is placed on the left side of the lens at a distance of \(30\,\text{cm}\), the magnification of the image will be: 
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).