Question:
When a body is thrown vertically upwards, from the ground, the time of ascent is \( t_1 \) and the time of descent is \( t_2 \) in the absence of air resistance. Then \( t_1 \) is equal to
When a body is thrown vertically upwards, from the ground, the time of ascent is \( t_1 \) and the time of descent is \( t_2 \) in the absence of air resistance. Then \( t_1 \) is equal to
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In vertical motion without air resistance, ascent time = descent time.
Updated On: Apr 21, 2026
- \( 2t_2 \)
- \( 0.5t_2 \)
- \( 0.25t_2 \)
- \( t_2 \)
- \( 4t_2 \)
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The Correct Option is D
Solution and Explanation
Concept:
Motion is symmetric under constant acceleration.
Step 1: Time of ascent.
\[ t_1 = \frac{u}{g} \]
Step 2: Time of descent.
From top to ground: \[ t_2 = \frac{u}{g} \] \[ \Rightarrow t_1 = t_2 \]
Step 1: Time of ascent.
\[ t_1 = \frac{u}{g} \]
Step 2: Time of descent.
From top to ground: \[ t_2 = \frac{u}{g} \] \[ \Rightarrow t_1 = t_2 \]
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