\( 6 \, \text{s} \)
The displacement is given by: \[ S = \frac{1}{2} t^2 - 6t \] To find the time at which the velocity is zero, we first find the velocity by differentiating the displacement with respect to time: \[ v = \frac{dS}{dt} = t - 6 \] Now, set \( v = 0 \) to find when the velocity becomes zero: \[ 0 = t - 6 \] Solving for \( t \): \[ t = 6 \, \text{s} \]
Thus, the time at which the velocity becomes zero is \( 6 \, \text{s} \).
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
A man loses 50% of his velocity after running a distance of 100 m. If his retardation is uniform, the distance he will cover before coming to rest is
Kepler's second law (law of areas) of planetary motion leads to law of conservation of