Step 1: Understanding the Concept
Selenium belongs to group 16 and has 6 valence electrons. In \(\text{H}_2\text{Se}\) it forms 2 bonds and keeps 2 lone pairs.
Step 2: Count
Steric number \(=2\) bond pairs \(+\) 2 lone pairs \(=4\).
Step 3: Conclusion
Four electron pairs mean \(sp^{3}\) hybridisation, like \(\text{H}_2\text{O}\).
Step 4: Compare the options
\(sp^{3}\) is option (C).
Final Answer:
The hybridisation in \(\text{H}_2\text{Se}\) is \(sp^{3}\).
\[ \boxed{\text{(C) }\mathrm{sp}^{3}} \]