Question:

What type of hybridisation is found in \(\mathrm{H}_2 \mathrm{Se}\) ?

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Count the bond pairs and lone pairs on selenium.
Updated On: Nov 13, 2026
  • sp

  • \(\mathrm{sp}^{2}\)

  • \(\mathrm{sp}^{3}\)

  • \(\mathrm{d}^{2}\mathrm{sp}^{3}\)

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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
Selenium belongs to group 16 and has 6 valence electrons. In \(\text{H}_2\text{Se}\) it forms 2 bonds and keeps 2 lone pairs.

Step 2: Count
Steric number \(=2\) bond pairs \(+\) 2 lone pairs \(=4\).

Step 3: Conclusion
Four electron pairs mean \(sp^{3}\) hybridisation, like \(\text{H}_2\text{O}\).

Step 4: Compare the options
\(sp^{3}\) is option (C).

Final Answer:
The hybridisation in \(\text{H}_2\text{Se}\) is \(sp^{3}\). \[ \boxed{\text{(C) }\mathrm{sp}^{3}} \]
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