Question:

What is the value of escape velocity on the Earth's surface?

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Escape velocity is independent of the object's mass and depends only on the planet. For Earth: \(11.2\,km/s\), for Moon: \(2.38\,km/s\). If velocity is less than escape velocity, the object will return due to gravity.
Updated On: Apr 18, 2026
  • \(7.9\,km/s\)
  • \(9.8\,km/s\)
  • \(11.2\,km/s\)
  • \(15\,km/s\)
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The Correct Option is C

Solution and Explanation

Concept: Escape velocity is the minimum velocity required for an object to escape from the gravitational field of a planet without further propulsion. The formula for escape velocity is: \[ v_e = \sqrt{\frac{2GM}{R}} \] where:
• \(G\) = gravitational constant
• \(M\) = mass of the Earth
• \(R\) = radius of the Earth

Step 1:
Understand dependence on planetary parameters. Escape velocity depends only on:
• Mass of the planet
• Radius of the planet It does not depend on the mass of the object being projected.

Step 2:
Substitute Earth's values. Using standard values for Earth: \[ v_e \approx 11.2\,km/s \]

Step 3:
Final result. \[ \boxed{11.2\,km/s} \]
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