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the height from earth s surface at which accelera
Question:
The height from earth's surface at which acceleration due to gravity becomes g/ where g is acceleration due to gravity on the surface of earth and R is radius of earth?
MHT CET
Updated On:
May 15, 2024
\(\sqrt2R\)
\(R\)
\(\frac{R}{\sqrt{2}}\)
\(2R\)
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The Correct Option is
B
Solution and Explanation
The correct option is (B):
\(R\)
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